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***Back_track*** · (This post was last modified: 04-03-2010 09:28 AM by Back_track.)

Code:

/*

 * Created by SharpDevelop.

 * User: Back_Track

 * Date: 4/2/2010

 * Time: 6:47 PM

 */

using System;

namespace nd_

{

    class Program

    {

        public static void Main(string[] args)

        {

            Console.WriteLine("Enter in Length of your char array: ");//Get user to input value

            int length = Int32.Parse(Console.ReadLine());

            char[] arr = new char[length];//create a char array with the length of the user input

            for(int i =0; i < length; i++)//Basic for loop

            {

                if(i % 2 == 0)//modulus operator to determine if even or odd

                {

                    arr[i] = 'x';//arr[number the loop is on] assign it the value of x

                }

                else{//If not even, odd

                    arr[i] = 'y';// arr[number loop in on] assign the value of y

                }

            }

            for ( int j = 0; j != length; j++)//Just for printing out our array

            {

                Console.WriteLine(arr[j] + "\t");//Write arr[value loop is on] then tab

            }

            Console.ReadLine();

        }

    }

}

FreckleS · 04-03-2010, 08:59 AM

Not bad, imo an example should be commented as much as possible to help the reader. Also are character arrays really needed in C#, why not just use string?

Good job on it though

***Back_track*** · 04-03-2010, 09:25 AM

I'll go though and add some comments, i just thought char arrays are just a good introduction to some parts of programming so .. i made this Tongue

FreckleS · 04-03-2010, 12:17 PM

Much better!

Like it now!

Yes char/arrays are very important parts of programming and a good way of learning about data types and memory.

***drdebcol*** · 04-03-2010, 06:32 PM

Very good example. On even positions are "x" characters and on odd "y".
Instead of "Int32.Parse" you could use "Convert.ToInt32" but that is the same.
Very good example !

***Back_track*** · 04-05-2010, 06:44 AM

Found a better way to find the odds than the else statement

Code:

if((i%2) != 0)

Basically, if If the remainder of i divided by two is anything other than 0 it assigns odd.

***drdebcol*** · 04-05-2010, 07:00 AM

(04-05-2010 06:44 AM)Back_track Wrote: Found a better way to find the odds than the else statement

Code:

if((i%2) != 0)
Basically, if If the remainder of i divided by two is anything other than 0 it assigns odd.

Or i think that odd number is if it is equal to 1 like :

Code:

if((i%2) == 1)

FreckleS · 04-05-2010, 07:18 AM

Good old modulus! Smile

Kirth · 08-25-2010, 08:49 PM

I don't quite get the purpose. Incidentally

Code:

char[] text = Console.ReadLine().ToCharArray();

foreach(char c in text)

{

    Console.WriteLine("{0}\t", c.ToString());

}

Poor code, 't is poor.